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你能解决七星谜题吗? – 译学馆
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你能解决七星谜题吗?

Can you solve the seven planets riddle? - Edwin F. Meyer

你的星际警队 已经将一群危险的叛乱者
Your interstellar police squadhas tracked a group of dangerous rebels
追至拥有七颗小星球的星团里
to a cluster of of seven small planets.
现在你必须在他们的援军赶来之前迅速将其逮捕
Now you must apprehend them quicklybefore their reinforcements arrive.
当然 叛乱者不会待在一个地方不动
Of course, the rebels won’t just stay put.
他们会在星球之间穿梭以躲避你
They’ll try to dodge youby moving from planet to planet.
但是你有一个很大的优势
But you have one major advantage.
每个小时 你先进的飞船可以在任意两个星球间穿梭
Every hour, your state-of-the-art cruisercan warp between any two planets,
而反叛者破烂的走私船
while their beat-up smuggling ship can only jump
只能在相邻两个星球之间移动
to an adjacent planet in that same time.
这些反叛者不喜欢原地不动
These rebels don’t like to stay put.
每次他们能转移的时候 就一定会转移
Every time they can relocate, they will.
侦查信息显示 叛乱者的舰队10小时内到达
Your scouts tell you that the approaching rebel fleet is 10 hours away.
你不能冒险让叛乱者逃掉
You can’t risk letting the rebels escape.
你能设计一个星球搜查顺序
Can you devise a sequencefor searching the planets
无论叛乱者如何穿梭
that’s guaranteed to catch themin 10 warps or less,
都能确保用不超过10次的移动抓住他们吗?
no matter what moves they make?
逮捕这些反叛者并不容易
Rounding up the rebels won’t be easy.
第一 你完全不知道
For one, you have no way
他们一开始是在哪个行星上
of knowing which planet they ’ re on to begin with.
这一信息的缺失
And without that information,
推测他们下一个落脚点 就非常困难了
it ’ s hard to determine where they ’ ll move next.
所以 该如何下手呢?
So where do you begin?
当遇到这一类问题时
When tackling problems
化繁为简是很有用的
of this kind it often helps to simplify things,
这会让你更好的理解他们的规律
so you can better understandtheir dynamics.
我们假设这个星团是这样相同的排列
Let’s imagine that this clusterhas the same arrangement
但没有最外面的星球 只保留中间四颗
but no outermost planets,leaving only the four in the center.
我们还是不知道反叛者从哪个星球开始
We still don’t know which planetthe rebels start on.
但是 现在有一个很重要的特征:
But there’s one key feature:
3号星球与所有其他的星球相邻
the third planetis adjacent to all others,
这就意味着 反叛者要么从3号星球开始 移动到别的星球
which means the rebels either start thereand move somewhere else,
要么从其他非3号星球开始
or start on one of the other planets
并且别无他法 只能移动到3号星球
and have no choicebut to move to planet three.
这样只需连续搜索两次3号星球就可以搞定了
Simply checking planet three twice in a row would do the trick.
把外面的星球加上就复杂多了
Adding the three outer planetadds a bit more complexity,
但策略不变 依然有效
but the same strategy remains.
我们想要按照一个
We want to check the planets
最终能围堵反叛者的顺序来搜索星球
in an order that will eventually corner the rebels.
另一个发现可以帮到我们:
And there’s another insightthat can help us:
每一小时 反叛者会从偶数星球
each hour, the rebels move froman even-numbered planet
移动到奇数星球 或者相反
to an odd-numbered planet, or vice versa.
这就为我们提供了简化方法
This gives us a wayto simplify the problem
即将这些星球分为两个子集
by dividing the planets into two subsets,
并分别处理两个子集
and tackling each one separately.
首先 我们假设反叛者从某个偶数星球开始:
For starters, let’s assume the rebelsbegin on an even-numbered planet:
可能是2号 4号 或者6号
either two, four, or six.
我们先从2号开始搜索
So we’ll search planet two first.
如果他们不在2号星球 那么他们一定是从4号或者6号开始
If they’re not there, they must havestarted on either four or six.
这表示他们可以飞到3号 5号 或者7号星球
which means they can move to three, five, or seven.
位于中间的3号星球
Planet three at the center gives
能给他们下一步提供最多的选择
them the most options for their next move,
因此 我们下一步就去搜查3号
so we’ll want to check there next.
如果没有发现他们
If we don ’ t find them,
那他们一定在5号或7号星球
they must have been at planet five
意味着他们下一步是去4号 或者6号星球
or seven, meaning they’ll next move to four or six.
现在我们去搜4号星球
Let’s now search planet four.
如果他们不在那儿
If they ’ re not there,
他们一定是去了第6号星球
they must have gone to the sixth planet
接下来只能飞往3号或7号星球
and can only flee to three or seven.
如果接下来搜索3号星球没有找到他们
If we next scour planet threeand don’t find them,
我们就知道他们一定去了7号星球 被逼到了角落
we know they went to planet sevenand are now cornered.
他们只能逃往6号星球
They can only move to planet six,
在那儿 我们将于第五次搜索时逮捕他们
where we ’ ll apprehend them on our fifth search.
当然 只有假设反叛者
Of course, this plan only works
是从偶数星球开始时 这个计划才有效
assuming that the rebels were on an even-numbered planet in the first hour.
如果那个假设错了怎么办?
But what if that assumption was wrong?
如果是那样 反叛者就一定是从奇数星球开始
In that case, they must’ve startedon an odd-numbered planet.
而因为他们每个小时移动至相邻星球
And because they move to an adjacentplanet every hour,
他们的位置必然是在奇偶星球间交替
their location must alternate betweenodd and even-numbered planets.
这意味着 如果他们
This means that if they were
从奇数星球开始
on an odd-numbered planet to start,
五次移动之后 他们会在一个偶数星球上
after five moves, they’d beon an even-numbered planet.
所以如果我们第五次搜索没找到他们
So if our first five searches missed them
由于我们的假设
because our assumption that they started
反叛者从偶数星球开始是错误的
on an even-numbered planet was wrong,
那么现在只需重复这个顺序再搜一次!
all we have to do nowis repeat the sequence!
按照2-3-4-3-6-2-3-4-3-6的顺序
Searching the planets in order two, three, four, three,
搜索这些星球
six, two, three, four, three, six,
让叛乱者无处可逃
leaves the rebels nowhere to run.
感谢你的演绎推理 星系秩序得以重塑
Thanks to your deductive reasoning,order is restored to the galaxy.

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译制信息
视频概述

如何演绎一场星际推理,抓住反叛者?

听录译者

收集自网络

翻译译者

Kirsten

审核员

审核员 V

视频来源

https://www.youtube.com/watch?v=dh4nEuhZBgg

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