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你能解开海怪之谜吗? – 译学馆
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你能解开海怪之谜吗?

Can you solve the sea monster riddle? - Dan Finkel

“没有隐藏在黑暗中的怪物 海洋会是什么样子? 就像一场无梦的睡眠”
——沃纳·赫尔左格
According to legend, once every thousand years
相传每过一千年
a host of sea monsters emerges from the depths to demand tribute
就会有大量海怪从深海中涌现出来
from the floating city of Atlantartica.
向水上之城亚特兰蒂卡要求献祭
As the ruler of the city, you’d always dismissed the stories…
作为城市的统治者 你总是对这些传说不屑一顾
until today, when 7 Leviathan Lords rose out of the roiling waters
直到今天 7位利维坦领主从汹涌的海面浮出来
and surrounded your city.
并且包围了你的城市
Each commands 10 giant kraken,
每个利维坦指挥着10个巨型海妖
and each kraken is accompanied by 12 mermites.
每个海妖都带有12个海妖虫
Your city’s puny army is hopelessly outmatched.
你弱小的城市军队毫无胜算
You think back to the legends.
你回想起了这个传说
In the stories, the ruler of the city saved his people
传说中 城市的统治者把珍珠作为赎金献给海怪
by feeding the creatures a ransom of pearls.
才得以挽救他的子民
The pearls would be split equally between the leviathans lords.
这些珍珠将会在利维坦领主中平均分配
Each leviathan would then divide its share into 11 equal piles,
然后每个利维坦会把自己的一部分平均分成11堆
keeping one, and giving the other 10 to their kraken commanders.
自己留下一堆 把另外10堆分给它的海妖首领
Each kraken would then divide its share into 13 equal piles,
每个海妖又会把它的部分平均分为13堆
keeping one, and distributing the other twelve to their mermite minions.
自己留下一堆 把剩余的12堆分给海妖虫下属
If any one of these divisions left an unequal pile or leftover pearl,
如果有任何一次分配不均或者有珍珠剩下
the monsters would pull everyone to the bottom of the sea.
海怪就会让所有人沉入海底
Such was the fate of your fabled sister city.
你传说中的姊妹城市即是如此命运
You rush to the ancient treasure room and find five chests,
你冲入祖先的宝库 发现了5个箱子
each containing a precisely counted number of pearls
每个箱子里都有精准计数的珍珠
prepared by your ancestors for exactly this purpose.
这些珍珠正是你祖先为今日之需而准备的
Each of the chests bears a number telling how many pearls it contains.
每个箱子上都有一个数字表示其中有多少珍珠
Unfortunately, the symbols they used to write digits 1,000 years ago
不幸的是 一千年前他们用来书写数字的符号
have changed with time,
已经随时间而发生了变化
and you don’t know how to read the ancient numbers.
你无法阅读这些古老的数字
With hundreds of thousands of pearls in each chest, there’s no time to recount.
每个箱子里有成千上万颗珍珠 没有时间重新数了
One of these chests will save your city
其中一个箱子可以拯救你的城市
and the rest will lead to its certain doom.
而其他的则无可避免地导致灭亡
Which do you choose?
你选择哪个呢?
Pause the video to figure it out yourself.
暂停视频 自己思考一下
Answer in 3
3秒后给出答案
Answer in 2
2秒后给出答案
Answer in 1
1秒后给出答案
There isn’t enough information to decode the ancient Atlantartican numeral system.
没有足够的信息来解码古老的亚特兰蒂卡数字系统
But all hope is not lost,
但是我们还有一线希望
because there’s another piece of information those symbols contain:
因为这些符号还包含了其他信息
patterns.
模式
If we can find a matching pattern in arabic numerals,
如果能找到这些符号与阿拉伯数字的对应关系
we can still pick the right chest.
我们仍可以选出正确的箱子
Let’s take stock of what we know.
我们分析一下已知信息
A quantity of pearls that can appease the sea monsters
一定数量的珍珠能够安抚海怪
must be divisible by 7, 11, and 13.
这个数必须能够被7 11和13整除
Rather than trying out numbers at random,
无需随机尝试数字
let’s examine ones that have this property
我们来测试一下满足这些特性的数字
and see if there are any patterns that unite them.
看看是否有办法把它们结合起来
Being divisible by 7, 11, and 13
能够被7 11和13整除
means that our number must be a multiple of 7, 11, and 13.
也就意味着这个数一定是7 11和13的倍数
Those three numbers are all prime, so multiplying them together
这三个数都是质数 把它们相乘
will give us their least common multiple: 1001.
就得到了它们的最小公倍数 1001
That’s a useful starting place
这个结论很有用
because we now know that any viable offering to the sea monsters
因为我们现在知道了任何提供给海怪的可行的数字
must be a multiple of 1001.
都必须是1001的倍数
Let’s try multiplying it by a three digit number,
我们把它和一个三位数相乘
just to get a feel for what we might get.
感受一下我们可能会得到什么
If we try 861 times 1001, we get 861,861,
用861乘以1001 得到861861
and we see something similar with other examples.
其他例子也是类似的排列方式
It’s a peculiar pattern.
这个排列方式很奇怪
Why would multiplying a three-digit number by 1001
为什么一个三位数乘以1001
end up giving you two copies of that number,
会得到两个该数
written one after the other?
其中一个在另一个之后呢?
Breaking down the multiplication problem can give us the answer.
把乘法问题分解一下就可以得到答案
1001 times any number x is equal to 1000x + x.
1001乘以任意数x等于1000x加上x
For example, 725 times 1000 is 725,000, and 725 x 1 is 725.
比如说 725乘以1000得725000 而725乘以1得725
So 725 x 1001 will be the sum of those two numbers: 725,725.
所以725乘以1001就是这两个数的和 725725
And there’s nothing special about 725.
725没有任何特殊之处
Pick any three-digit number,
任意选择一个三位数
and your final product will have that many thousands, plus one more.
乘积都会为该数字的1000倍再加上该数
Even though you don’t know how to read the numbers on the chests,
即使你不知道怎么阅读箱子上的数字
you can read which pattern of digits represents a number divisible by 1001.
你也可以看出哪个数字排列方式表示能被1001整除
As with many problems, trying concrete examples
就像很多问题一样 尝试一个具体的例子
can give you an intuition for behavior that may at first look abstract and mysterious.
可以让你直观地理解乍一看抽象且神秘的行为
The monsters accept your ransom and swim back down to the depths
海怪接受了你的赎金 游回了大海深处
for another thousand years.
等待着下一个千年的到来
With the proper planning,
有了合适的计划
that should give you plenty of time to prepare for their inevitable return.
你便有足够的时间来为它们下一次不可避免的到来做准备

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视频概述

你能解开海怪之谜,找到正确的箱子,避免城市的毁灭吗?

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视频来源

https://www.youtube.com/watch?v=YytHuow4VnU

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