ADM-201 dump PMP dumps pdf SSCP exam materials CBAP exam sample questions

你能解开这个锁的难题吗? – 译学馆
未登录,请登录后再发表信息
最新评论 (0)
播放视频

你能解开这个锁的难题吗?

Can you solve the locker riddle? - Lisa Winer

你富有的 古怪的叔叔刚去世
Your rich, eccentric uncle just passed away,
你和99个品行不端的亲戚被邀请来 听读他的遗嘱
and you and your 99 nasty relatives have been invited to the reading of his will.
他想把所有的财产都留给你
He wanted to leave all of his money to you,
但是他知道 如果这样做了 你的亲戚们就会永远纠缠你
but he knew that if he did, your relatives would pester you forever.
所以他一直寄希望于
So he is banking on the fact
曾教过你的关于谜语你要知道的一切
that he taught you everything you need to know about riddles.
你叔叔在他的遗嘱中留下了一段话:
Your uncle left the following note in his will:
“我设计了一个迷题
“I have created a puzzle.
如果你们100个人一起答出 那就平分这笔遗产
If all 100 of you answer it together, you will share the money evenly.
可是 如果你们当中谁最先 在没有任何人帮助下
However, if you are the first to find the pattern and solve the problem
解开谜团
without going through all of the leg work,
就会得到全部遗产
you will get the entire inheritance all to yourself.
祝你们好运”
Good luck.”
律师将你和你的亲戚们带到府邸的一个秘密房间里
The lawyer takes you and your 99 relatives to a secret room in the mansion
那里有100把锁
that contains 100 lockers,
每一把锁暗藏一个单独的字母
each hiding a single word.
律师解释说:
He explains:
每个亲戚都会被分到1到100中的一个数字
Every relative is assigned a number from 1 to 100.
继承人1会打开所有的锁
Heir 1 will open every locker.
每隔1把 继承人2就会把锁锁上
Heir 2 will then close every second locker.
每隔2把 继承人3就会改变锁的状态
Heir 3 will change the status of every third locker,
特别是如果锁是开着的 那她就会锁上
specifically if it’s open, she’ll close it,
但是如果是上锁的 那她就会打开
but if it’s closed, she’ll open it.
按照这个模式持续下去 直到你们100个人都做完
This pattern will continue until all 100 of you have gone.
最终仍开着的锁含有的词语
The words in the lockers that remain open at the end
会帮助你破解保险箱的密码
will help you crack the code for the safe.
还没等堂兄萨帝厄斯开始
Before cousin Thaddeus can even start down the line,
你就上前告诉律师 你知道哪些锁会一直开着
you step forward and tell the lawyer you know which lockers will remain open.
但是怎样知道的呢?
But how?
如果你想自己思考一下 那就先暂停视频
Pause the video now if you want to figure it out for yourself!
解密倒数:3
Answer in: 3
2
Answer in: 2
1
Answer in: 1
问题的关键在于要意识到一把锁被触碰的次数
The key is realizing that the number of times a locker is touched
与这把锁的序号的因数相同
is the same as the number of factors in the locker number.
比如 序号是6的那把锁
For example, in locker #6,
第一个人会打开它
Person 1 will open it,
第二个人会锁上它
Person 2 will close it,
第三个人会打开它
Person 3 will open it,
第六个人会锁上它
and Person 6 will close it.
数字1 2 3和6都是序号6的因数
The numbers 1, 2, 3, and 6 are the factors of 6.
所以假设一把锁有偶数个因数时
So when a locker has an even number of factors
它就会一直锁着
it will remain closed,
当它的因数是奇数时
and when it has an odd number of factors,
它就会一直开着
it will remain open.
大多数的锁都有偶数因数
Most of the lockers have an even number of factors,
这就可以理解了 因为因数可以自然配对
which makes sense because factors naturally pair up.
事实上 只有锁的序号包含奇数因数的时候
In fact, the only lockers that have an odd number of factors
才能构成完全平方
are perfect squares
因为那些拥有一个因数的数字 乘它本身的数字就等于那个序号
because those have one factor that when multiplied by itself equals the number.
比如序号为9的那把锁 1可以打开它
For Locker 9, 1 will open it,
3会锁上它
3 will close,
9会打开它
and 9 will open it.
3乘3等于9
3 x 3 = 9,
但是3只能被数一次
but the 3 can only be counted once.
因此 每一把锁的序号是完全平方的时候 就会一直开着
Therefore, every locker that is a perfect square will remain open.
你就知道有10把锁是解题的关键
You know that these ten lockers are the solution,
于是你立刻打开它们 看到里面的词:
so you open them immediately and read the words inside:
“密码是被触碰两次的前五把锁”
“The code is the first five lockers touched only twice.”
你就明白了 只被触摸两次的锁 才会成为质数
You realize that the only lockers touched twice have to be prime numbers
因为每个质数只有两个因数:
since each only has two factors:
1和它本身
1 and itself.
所以密码是235711
So the code is 2-3-5-7-11.
律师把你带到保险箱那里
The lawyer brings you to the safe,
你会继承你的遗产
and you claim your inheritance.
你的心术不正的亲戚们一直忙着互相算计
Too bad your relatives were always too busy being nasty to each other
注意不到你古怪叔叔的迷题
to pay attention to your eccentric uncle’s riddles.

发表评论

译制信息
视频概述

解决秘密的关键在于这个数字的构成,你知道了么。

听录译者

收集自网络

翻译译者

喋喋

审核员

审核团V

视频来源

https://www.youtube.com/watch?v=c18GjbnZXMw

相关推荐